Can someone confirm the following error with python on iPhone? I'm trying to use urllib to access a website but I'm getting a socket error...

Code:

import urllib
test = urllib.urlopen("http://www.google.com")

I'm getting the following on the phone:

Code:

Python 2.5.1 (r251:54863, Jul 27 2007, 12:05:57) 
[GCC 4.0.1 LLVM (Apple Computer, Inc. build 2.0)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import urllib
>>> test = urllib.urlopen("http://www.google.com/")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.5/urllib.py", line 82, in urlopen
    return opener.open(url)
  File "/usr/lib/python2.5/urllib.py", line 190, in open
    return getattr(self, name)(url)
  File "/usr/lib/python2.5/urllib.py", line 325, in open_http
    h.endheaders()
  File "/usr/lib/python2.5/httplib.py", line 856, in endheaders
    self._send_output()
  File "/usr/lib/python2.5/httplib.py", line 728, in _send_output
    self.send(msg)
  File "/usr/lib/python2.5/httplib.py", line 695, in send
    self.connect()
  File "/usr/lib/python2.5/httplib.py", line 663, in connect
    socket.SOCK_STREAM):
IOError: [Errno socket error] (4, 'Non-recoverable failure in name resolution')

Any ideas?

This code works:

opener = urllib.URLopener()
f = opener.open(url)
f.read()

Originally Posted by lh99

This code works:

opener = urllib.URLopener()
f = opener.open(url)
f.read()

i tried this... it doesn't work